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Oksana_A [137]
4 years ago
6

Which function is the inverse of f(x)=b^x

Mathematics
2 answers:
lara31 [8.8K]4 years ago
7 0

Answer:

Answer is F^1(y)= logb^y

Step-by-step explanation: Apex:)

max2010maxim [7]4 years ago
6 0

Here we are given the function:

f(x)=b^{x}

Steps to find inverse are :

Step 1:

First replace f(x) by y.

y=b^{x}

Step 2:

Replace every  x with a  y and replace every  y with an  x.

x=b^{y}

Step 3:

Solve the equation from step 2 for y.

x=b^{y}

Taking log on both sides:

logx=log(b^{y})

logx=ylogb

y=\frac{logx}{logb}

Answer:

Inverse function is :

y=\frac{logx}{logb}

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Which of the following angles has a reference angle of pi/12
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Given:

\frac{\pi}{12}

Required:

To calculate reference angle

Explanation:

\frac{19\pi}{12}

Required answer:

Option B

5 0
1 year ago
1. Find the measure of each of the following angles in the rhombus
balu736 [363]

Answer:

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8 0
3 years ago
without using your calculator or computer graphing tool. match each function rule with its graph. In each case, write a sentence
valentinak56 [21]
Well I know that c. goes with I. just because I saw so many x^3 graphs.

For a. the parent function is x^2, so 0.5x^2 should look about the same as x^2, so the answer is VI.



4 0
4 years ago
How can you indentify the opposite and the absolute value of a rational number?
defon
View the absolute value of a number as its distance from zero. When you take the absolute value of a number, you always end up with a positive number (or zero). Whether the input was positive or negative (or zero), the output is always positive (or zero).

Hope it helped
5 0
3 years ago
Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

f''(x)=9-\frac{3}{x}

We need to find Third-order derivative of the function f(x).

f''(x)=9-\frac{3}{x}=9-3x^{-1}

We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}

f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}

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Therefore, f'''(x)=\frac{3}{x^{2}}

4 0
4 years ago
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