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OlgaM077 [116]
3 years ago
12

Factor completely x^4-17x^2+16​

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

(x - 1) (x + 1) (x - 4) (x + 4)

Step-by-step explanation:

actor the following:

x^4 - 17 x^2 + 16

x^4 - 17 x^2 + 16 = (x^2)^2 - 17 x^2 + 16:

(x^2)^2 - 17 x^2 + 16

The factors of 16 that sum to -17 are -1 and -16. So, (x^2)^2 - 17 x^2 + 16 = (x^2 - 1) (x^2 - 16):

(x^2 - 1) (x^2 - 16)

x^2 - 16 = x^2 - 4^2:

(x^2 - 1) (x^2 - 4^2)

Factor the difference of two squares. x^2 - 4^2 = (x - 4) (x + 4):

(x - 4) (x + 4) (x^2 - 1)

x^2 - 1 = x^2 - 1^2:

(x^2 - 1^2) (x - 4) (x + 4)

Factor the difference of two squares. x^2 - 1^2 = (x - 1) (x + 1):

Answer: (x - 1) (x + 1) (x - 4) (x + 4)

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Step-by-step explanation:

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