Ask question

Ask question

All categories

3 years ago

9

Write the converse of this statement.

1 answer:

rusak2 [61]3 years ago

8 0

If two angles are equal, then they are both obtuse

You might be interested in

1) To the nearest tenth of a foot, what is the distance from the wall to

steposvetlana [31]

Answer:

1) B

2) 4.5 feet

Step-by-step explanation:

Please see the attached picture for the full solution.

6 0

3 years ago

The ratio of the measures of the three angles is 4:5:6. Find the measure of each angle of the triangle

Furkat [3]

Answer:

Let the number be x.

Given the statement: The ratio of the measure of the three angles is, 4 : 5 : 6.

Then, the angles be 4x , 5x and 6x respectively.

We know that: The sum of all the measures of angles is 180 degree.

then;

$4x+5x+6x = 180^{\circ}$

Combine like terms;

$15x = 180^{\circ}$

Divide by 15 both sides we get;

$x = 12$

Then, the measure of each angle of triangle:

$4x = 4(12) = 48^{\circ}$

$5x = 5(12) = 60^{\circ}$

$6x = 6(12) = 72^{\circ}$

4 0

3 years ago

In the figure below, if the radius of circle o

Aliun [14]

Answer:

The length of AC is 10 units

Step-by-step explanation:

In the given circle O

∵ AOCB is a rectangle

∵ OB and AC are the diagonals of the rectangle AOCB

∵ Diagonals of the rectangle are equal in lengths

→ That means OB and AC are equal in lengths

∴ OB = AC

∵ O is the center of the circle

∵ B is a point on the circle

∴ OB is a radius of the circle O

∵ The radius of the circle is 10 units

∴ OB = 10 units

∵ OB = AC

∴ AC = 10 units

∴ The length of AC is 10 units

5 0

3 years ago

Check all solutions to the equation. If there are no solutions, check "None."x2=0A. 1B. -1C.0D. 10E. 4E None

Juli2301 [7.4K]

The given equation is,

$\begin{gathered} x^2=0 \\ x=0 \end{gathered}$

Thus, option (C) is the correct solution.

8 0

1 year ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago