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2 years ago

Find the value of n-7 when n=17.

Mathematics

2 answers:

vekshin12 years ago

8 0

Answer:

Step-by-step explanation:

17-7=10

marta [7]2 years ago

6 0

Answer:

Step-by-step explanation:

f(x) = n - 7

f(17) = 17 - 7

f(17) = 10

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A house worth $180,000 has a coinsurance clause of 75 percent. The owners insure the property for $101,250. They then have a los

Bess [88]

Answer:

$37,500

Step-by-step explanation:

We have been given that a house worth $180,000 has a coinsurance clause of 75 percent. The owners insure the property for $101,250. They then have a loss that results in a $50,000 claim.

We will use loss settlement formula to solve our given problem.

$\text{Loss settlement}=\frac{\text{Loss}\times\text{Limit of insurance}}{\text{Actual cash value}\times \text{Coinsurance}\%}$

Upon substituting our given values, we will get:

$\text{Loss settlement}=\frac{\$50,000\times\$101,250}{\$180,000\times 75\%}$

$\text{Loss settlement}=\frac{\$50,000\times\$101,250}{\$180,000\times 0.75}$

$\text{Loss settlement}=\frac{\$5,062,500,000}{\$135,000}$

$\text{Loss settlement}=\$37,500$

Therefore, they will receive $37,500 from insurance.

5 0

3 years ago

Use the grouping method to factor the polynomial below x^3 -4x^2+3x-12

olasank [31]

Answer:

x^2(x-4) + 3(x-4)

(x^2 + 3)(x-4)

Step-by-step explanation:

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2 years ago

A school flag poll casts a 16 foot shadow on the lawn. A teacher stood at the shadows edge and measure the angle of elevation to

vovikov84 [41]

Answer:

30.1 feet.

Step-by-step explanation:

We have been given that a school flag poll casts a 16 foot shadow on the lawn. A teacher stood at the shadows edge and measure the angle of elevation to the top of the poll at 62°. We are asked to find the height of the tall.

First of all, we will draw a diagram to represent our give scenario as shown in the attachment.

We can see that side length with 16 feet is adjacent side and height of the pole (h) is opposite side to angle of elevation.

We know that tangent relates opposite side of a right triangle to its adjacent side.

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$