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Bogdan [553]
3 years ago
14

A fence post that is 2 meters tall cast a shadow that is 1.6 meters. How tall is a tree that cast a shadow of 24 meters?

Mathematics
1 answer:
NeX [460]3 years ago
5 0
2f..........1.6m \\ x............24m \\\\ x=\frac{2*24}{1.6} \\\\ x=2*15 \\\\ \boxed{x=30 m \ has \ the \ tree}
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Find the sum of the A.P:8,-3,-2,-7,-12....up to n terms​
Ira Lisetskai [31]

Answer:

\frac{21n}{2} -\frac{5n^{2} }{2}

Step-by-step explanation:

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[the second term should be +3 or else it wont form AP series]

first term in the series: 8

common difference : 3-8 = -5

total terms : n

  • the formula for sum of n terms in an ap = \frac{n}{2} [2a+(n-1)d]

a: first term

d: common difference

n : total terms

  • by substituting value in the above formula,
  • sum of the A.P: \frac{n}{2} [2(8)+(n-1)-5]

\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+-5n+5]

\frac{n}{2} [21+-5n]

=\frac{21n}{2} -\frac{5n^{2} }{2}

6 0
4 years ago
PLEASEEEE PLEASEEEEEEEEE HELPPPPPPPPPP<br> how do i solve this equation?
Stells [14]

Answer:

360

Step-by-step explanation:

using the definition

n P_{r} = \frac{n!}{(n-r)!}

where n! = n(n - 1)(n - 2)..... × 3 × 2 × 1

then

6P_{4}

= \frac{6!}{(6-4)!}

= \frac{6!}{2!}

= \frac{6(5)(4)(3(2)(1)}{2(1)} ← cancel 2(1) on numerator / denominator

=  6 × 5 × 4 × 3

= 360

7 0
2 years ago
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