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NARA [144]
3 years ago
11

Round 90608.5881594 to 1 decimal place

Mathematics
2 answers:
lana66690 [7]3 years ago
5 0
Which decimal place?

mars1129 [50]3 years ago
3 0
An integer whose absolute value is greater than itself
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a car can complete a journey of 300 km with a speed of 60 km per hour I) how much does it take the to complete the journey and w
Verdich [7]

Step-by-step explanation:

First step:

Distance = 300km

Speed = 60km/hr

We know,

Using Speed = Distance ÷ Time

Time = Distance ÷ Speed

we have Total Time = 300÷60

Total Time = 5hr

Again,

Distance = 200km. (Time = 5hr,

Speed =? Distance = 200)

Speed = Distance÷ Time

= 200÷5

= 40km/hr

6 0
4 years ago
The height of Figure A is doubled to create Figure B. How will the surface area be affected?
likoan [24]

Answer:

dont click the link

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the slope of the line through (3, 2) and (-3 ,4)
Delicious77 [7]

Answer:

Slope = -\frac{2}{3}

Step-by-step explanation:

Slope = \frac{rise}{run}

Slope = \frac{y2-y1}{x2-x1}

Slope = \frac{4-2}{-3-3}

Slope = -\frac{4}{6}

Slope = -\frac{2}{3}

4 0
4 years ago
Read 2 more answers
Rationalize the denominator of the given expression
Grace [21]

You multiply top and bottom of the fraction by the conjugate of 5 - √2  which is 5 + √2.   This produces a rational denominator:-

=    √7 ( 5 + √2)  /   (5 - √2)(5 + √2)

=  √7 ( 5 + √2) /   (25 -2)

=   (√7 ( 5 + √2)) / 23    answer


6 0
4 years ago
Y= |x−3| + |x+2| − |x−5|, if x&gt;5<br> I need to know what y equals.
olganol [36]

Answer:

y  \ge9

Step-by-step explanation:

The given function is

y =  |x - 3|   +  |x  + 2|  -  |x - 5|

By the triangle inequality property,

|x + y|  \leqslant  |x|  +  |y|

and the alternate triangle inequality property;

|x - y|  \geqslant  |x|  -  |y|

We apply this property to get:

y  \geqslant   |x |    - |3|    +  |x |  +  |2|  -(  |x |  -  |5| )

Expand parenthesis to get:

y  \geqslant   |x |    - |3|    +  |x |  +  |2|  - |x |   +   |5|

Simplify to get:

y  \geqslant   |x |    - 3+  |x |  +  2- |x |   +   5

Group similar terms to get:

y  \geqslant   |x |  +   |x | - |x |    - 3 + 2+   5

y  \geqslant   |x |   + 4

When x>5,

y  \geqslant   |5 |   + 4

That's;

y  \geqslant   5  + 4   \\ y  \geqslant   9

5 0
3 years ago
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