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elixir [45]
2 years ago
14

I was sick the day that the class went over how to do this and I don’t know how to do it.

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
6 0
You first need to know the equation A=pi x r^2. The equation you need for this problem is pi (3.14) x 3^2
You might be interested in
1.) p^2+14p-38=0<br> what the vertex?
Lelu [443]

Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

x_{vertex } = - \frac{14}{2} = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)


3 0
3 years ago
Calculate the quotient below and give your answer in scientific notation.<br> 2.64*10^-3\8.0*10^0
Zolol [24]

Answer:

The quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0} is: \mathbf{3.3\times 10^{-4}}

Step-by-step explanation:

We need to find quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}

We know that 10^0=1

Now solving:

\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}\\=\frac{2.64\cdot 10^{-3}}{8.0}\\=\frac{0.00264}{8}\\=0.00033

Writing it in scientific notation

0.00033\\=3.3\times10^{-4}

So, the quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0} is: \mathbf{3.3\times 10^{-4}}

3 0
3 years ago
Select the correct answer. What is the domain of the function represented by this graph?
devlian [24]

Answer:

Doman is the x intercpet range

Step-by-step explanation:

all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.

8 0
3 years ago
Explain why every other number is an even number.
ICE Princess25 [194]
Even numbers can be divided into two equal groups while odd numbers cannot so every other number is an even number because it can be divided into two equal groups
4 0
3 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
2 years ago
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