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lidiya [134]
2 years ago
12

PLEASE HELP WITH THIS PLEASE.

Mathematics
1 answer:
Kryger [21]2 years ago
3 0

Answer:

C

Step-by-step explanation:

(a^2+b^2)^2=a^2+b^2

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What is the formula for the discriminant?
Dennis_Churaev [7]

Answer:

In the case of a quadratic equation ax2 + bx + c = 0, the discriminant is b2 − 4ac; for a cubic equation x3 + ax2 + bx + c = 0, the discriminant is a2b2 + 18abc − 4b3 − 4a3c − 27c2.

Step-by-step explanation:

4 0
3 years ago
What is the gross pay per pay period?
Vinil7 [7]

Divide 71,290 with 2

71,290 / 2 = 35,645

Then, divide 35,645 with 12 ( because theres 12 months in 1 year )

35,645 / 12 = 2970.42

a) 2970.42 is your answer.

3 0
3 years ago
A 15% discount saves you $5 off the price of an electronic game. How much do you save off the regular price if the discount is w
chubhunter [2.5K]

Answer:

The 45% off discount saves an additional $10 compared to the 15% discount for a total of $15 off regular price.

Step-by-step explanation:

We can find the original price of the game through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio  of $ to $. Since 15% of 100% is the same ratio as $5 to the unknown original $ price, I write:

\frac{15}{100} =\frac{5}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

15y=100(5)\\15y=500

I now solve for y by dividing by 15.

\frac{15y}{15} =\frac{500}{15} \\y= 33.33333....

The original price was $33.34.

Now, we can find the amount if 45% off and then then compare the two discounts. To find the percent off I can multiply by 0.45(33.34)=15. The 45% off discount saves an additional $10 compared to the 15% discount.

4 0
3 years ago
14389+4309 what is it
kow [346]
The answer is 18,698 :)

8 0
3 years ago
Read 2 more answers
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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