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irga5000 [103]
3 years ago
10

Can the absoulute value of a number ever be a negative number?

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0
No they can not be a negative number
Alecsey [184]3 years ago
4 0

Answer:

An absolute value of a number is never a negative number.

Step-by-step explanation:

An absolute value of a number describes the distance of a number on a numberline from 0 without considering which direction from 0 the number is.


Hope this helps

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While shopping for clothes, Daniel spent $32 less than 2 times what Jaclyn spent. Daniel Spent $24. Write and solve an equation
AlladinOne [14]

Answer:

2x-32=24

Step-by-step explanation:

2x-32=24

2x=56

x=28

Hope this helps!

8 0
2 years ago
67,000 rounded to the nearest ten thosand
mojhsa [17]
70,000 is the answer.
<span>Round the number BEHIND the ten thousand</span>
3 0
3 years ago
Read 2 more answers
Here is the problem
anygoal [31]

Answer:

5 =x

Step-by-step explanation:

The top and the bottom are the same length

17 = 3x+2

Subtract 2 from each side

17-2 = 3x+2-2

15 =3x

Divide by 3

15/3 = 3x/3

5 =x

5 0
3 years ago
Read 2 more answers
What is the type of conic section given by the equation x^2 - 9y^2 = 900 and what is the domain and range?
Valentin [98]
A conic section is a curve obtained by the intersection of the surface of a cone with a plane. A conic section can be a circle, a hyperbola, a parabola, and an ellipse.

For a circle, the general equation of a circle with center, (a, b), and a radius, r, is of the form
(x-a)^2+(y-b)^2=r^2

For a hyperbola, the general equation of a hyperbola with center (h, k), and a and b half the lengths of the major and the minor axis respectively is of the form.
\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} =1

For a parabola, the general equation of a parabola with center (h, k), and a multiplier a is of the form
y-k=a(x-h)^2

For an ellipse, the general equation of an ellipse with center (h, k), and a and b half the lengths of the major and the minor axis respectively.
\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} =1

Given the equation
x^2-9y^2=900
It can be rewritten as
\frac{(x-0)^2}{900} - \frac{(y-0)^2}{100} =1 \\  \\ \frac{(x-0)^2}{30^2} - \frac{(y-0)^2}{10^2} =1
This gives an equation of a hyperbola with center (0, 0), half the length of the major axis = 30 and half the length of the minor segment = 10.

The domain of the equation is all real values of x.
8 0
4 years ago
hellppppp,mr. Raymond told students in a true-false quiz with 10 questions you are certain to get five correct if you just guess
Aleks [24]

Answer:

No

Step-by-step explanation:

Cause it just doesnt not making is sence

3 0
3 years ago
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