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motikmotik
2 years ago
7

Is it only me or does every body feel stressed about all the work they get from school?!

Mathematics
2 answers:
prisoha [69]2 years ago
8 0

Answer:

Me too

Im so ready for School to be over

Step-by-step explanation:

Anna11 [10]2 years ago
3 0

Answer:

I don’t get stressed out, it’s just they do too much.

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Find the number the comes next 1.2.6,21.88,?​
Nataly_w [17]

Answer

455

Step-by-step explanation:

(1×1) + 1 = 2

(2×2) + 2 = 6

(6×3) + 3 = 21

(21×4)+4 = 88

(88×5)+5 = 445

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28%20-%20x%20%2B%203%29%20-%20%284x%20-%2010%29" id="TexFormula1" title="( - x + 3) - (4x - 1
VladimirAG [237]

Answer:

-5x+13 given (-x+3)-(4x-10)

Answer:-5x+13

Step-by-step explanation:

We are going to distribute to get rid of the ( ):

-x+3-4x+10

Pair up like terms:

-x-4x+3+10

Combine the like terms:

-5x+13

5 0
3 years ago
Read 2 more answers
6 − 3.98 what is the answerrrrr
NARA [144]

Answer:

2.02 is what i got

3 0
3 years ago
Read 2 more answers
Since the area under the normal curve within two standard deviations of the mean is 0.95, the area under the normal curve that c
alukav5142 [94]

Answer:

X \sim N (\mu ,\sigma)

And for this case we know this condition:

P(\mu-2\sigma

By the complement rule we know that:

P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05

But since the distribution is symmetrical we know that:

P(X\mu +2\sigma) = 0.025

So then the statement for this case is FALSE.

b. False

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

X \sim N (\mu ,\sigma)

And for this case we know this condition:

P(\mu-2\sigma

By the complement rule we know that:

P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05

But since the distribution is symmetrical we know that:

P(X\mu +2\sigma) = 0.025

So then the statement for this case is FALSE.

b. False

5 0
3 years ago
NEED HELP the answers are
adelina 88 [10]

Answer:

6 days

Step-by-step explanation:

The can relatively small... I would just say common sense.

hopefully this helps luv <3

8 0
2 years ago
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