What is 25 - 14+ 43 using pemdas
2 answers:
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Answer:
y
=
3
2
x
Rewrite in slope-intercept form.
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y
=
3
2
x
Use the slope-intercept form to find the slope and y-intercept.
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Slope:
3
2
y-intercept:
(
0
,
0
)
Any line can be graphed using two points. Select two
x
values, and plug them into the equation to find the corresponding
y
values.
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x
y
0
0
2
3
Graph the line using the slope and the y-intercept, or the points.
Slope:
3
2
y-intercept:
(
0
,
0
)
x
y
0
0
2
3
image of graph
Step-by-step explanation:
Answer:
The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.
Step-by-step explanation:
Use the trick of transforming the given random variable one that is standard normal distributed, aka a z-score, then look up the two percentile values in z-score tables to get two equations with two unknowns.
So, let x be the variable describing the marks of a student, and
the standardized equivalent of that (mu - mean, sigma - standard deviation).
We are looking for values of mu and sigma. At this point we'd be out of luck, but, wait, we're given two bits of info: the 10% point (aka, 90th percentile) and the 20% point (can be interpreted as 100-20th percentile). For each point we can use z-score tables to look up the corresponding values of z (just search for z tables). I found:
z-score for the 10% point: z_10=1.28
z-score for the 20% point: z_20=-0.84
That gives us two equations:
and can be solved for mu and sigma (do the work on your end, I am showing my result):
The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.