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3 years ago

You roll a regular six-sided cube

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

Answer:

1/36

Because TO Roll It once it would take 1/6 So Multiply On 6

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If pq=3 and pq+rs=5, then 3+rs=5 is an example of the _________.

Mrrafil [7]

<span>This is an example of the substitution property of equality, meaning that if pq = 3, you may substitute 3 for pq in another related equation. So if pq+rs=5 is true, then 3+rs=5 is true as well.</span>

8 0

3 years ago

Miguel invests money in an account paying simple interest. He invests $170 and no money is added or removed from the investment.

stiv31 [10]

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$185.30\\ P=\textit{original amount deposited}\dotfill & \$170\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &1 \end{cases} \\\\\\ 185.30=170[1+(\frac{r}{100})(1)]\implies \cfrac{185.30}{170}=1+\cfrac{r}{100}\implies \cfrac{109}{100}=\cfrac{100+r}{100} \\\\\\ 109=100+r\implies \stackrel{\%}{9}=r$

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2 years ago

You call 5 friends, tomorrow you call 5 more. Write an equation.

ElenaW [278]

Answer:

5+5=10

Step-by-step explanation:

5+5=10

hope it helps. plz mark me as brainliest.

7 0

3 years ago

A cheese pizza costs $5. Additional toppings cost $1.50 each. Write and graph an equation that represents the total cost $c$ (in

Triss [41]

Answer:

5 + 1.5x = total cost

Step-by-step explanation:

5 is for one pizza and x is for toppings. For every topping it is multiplied by 1.5. for example, if you have 2 toppings for one cheese pizza it would be 5 dollars + 1.5x2 which is 3 so 3+5=8$ in total.

7 0

3 years ago

Read 2 more answers

Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).

Korolek [52]

Answer:

$c = \dfrac{25}{4}$

$b = \dfrac{-13}{8}$

$a = \dfrac{11}{8}$

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

$c = \dfrac{25}{4}$

$b = \dfrac{-13}{8}$

$a = \dfrac{11}{8}$

6 0

3 years ago