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Wittaler [7]
3 years ago
14

I'm not sure understanding this at ALLLLL

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

17. Scale Factor is  3:1

18. Scale Factor is  1:3

Step-by-step explanation:

Scale Factor: In two similar shapes, the ratio of their corresponding sides is called scale factor.

17. Give the scale factor of Figure A to Figure B

Figure A has sides:

Hypotenuse = 15

Perpendicular = 12

Base = 9

Figure B has sides:

Hypotenuse = 5

Perpendicular = 4

Base = 3

So, if we divide all sides of figure A by 3 we get Figure B

So, Figure A : Figure B

3:1

18. Give the scale factor of Figure B to Figure A

Figure B has sides:

Hypotenuse = 5

Perpendicular = 4

Base = 3

Figure A has sides:

Hypotenuse = 15

Perpendicular = 12

Base = 9

If we multiply 3 with the sides of Figure B we can get the sides of Figure A.

So scale factor is 3.

So, Figure B : Figure A

1:3

Ivan3 years ago
5 0

Answer:

17) 3 : 1

18: 1 : 3

Step-by-step explanation:

Figure A and Figure B are similar triangle.

Scale Factor of A : B

= 9 : 3

= 3 : 1

Scale Factor of B : A

= 3 : 9

= 1 : 3

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For every 20 penguins at the North Pole there are 9 polar bears. If you encountered 27 polar bears, how many penguins would you
cluponka [151]

Answer:

60 penguins

Step-by-step explanation:

We need to find out how many times 9, the number of polar bears for every 20 penguins, was multiplied by, so that we can multiply 20 penguins by the same amount.

27/9 = 3

20*3 = 60

5 0
3 years ago
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den301095 [7]
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20 + 6
26

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3 years ago
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What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x
lora16 [44]
\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}

We can begin by rearranging this into multiplication:

\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}

Now we can factor the numerators and denominators:

\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}

The factors (x+4) and (x+2) cancel out, leaving us with:

\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}

Our answer comes out to be:

\frac{(x-4)^{2} }{(x+3)(x+1)} or \frac{ x^{2} -8x+16}{ x^{2}+4x+3 }

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4
4 0
3 years ago
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
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Lilit [14]

Answer:

130.5

Step-by-step explanation:

similar shapes have proportional sides so divide 18/27 to get the proportion then multiply each side of the smaller polygon by the proportion to get the sides for the larger polygon and add the larger polygons sides together.

8 0
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