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3 years ago

1. Round this number to the nearest hundred.

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

Answer:

1. 320 2. 580

Step-by-step explanation:

when you round 320, it is 320 because the hundredths place is 0, which is under 5 so the numbers wouldn't change.

When you round 579, the hundredths place is a 9, which is over 5 so you add 1 to seven to get 8.

vlabodo [156]3 years ago

3 0

1: it would be 300 because if the middle is below 5 you would round down. 2: it would be 600 because the middle number is above 5. hope this helped!

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8n^2-4(7m^3+5n^2)<br> help

Rasek [7]

Hello there!

8m² - 4(7m³ + 5n²)

You wanna start by using the distributive property

=8n² - (-4)(7m³) + (-4)(5n²)

= 8n² - 28m³ - 20n²

= -28m³ - 12m²

7 0

2 years ago

How much money must be deposited now in an

Liono4ka [1.6K]

Answer:

$\$487.48$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ A=\$1,000\\ r=7.25\%=7.25/100=0.0725\\n=4$

substitute in the formula above

$1,000=P(1+\frac{0.0725}{4})^{4*10}$

$1,000=P(\frac{4.0725}{4})^{40}$

$P=1,000/(\frac{4.0725}{4})^{40}$

$P=\$487.48$

5 0

3 years ago

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

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3 years ago

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kati45 [8]

ok Step-by-step explanation:

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2 years ago

The world’s population is currently estimated at 7,125,000,000. What is this to the nearest billion? billion

Oksana_A [137]

Answer:

7,000,000,000

Step-by-step explanation:

since the closest number is less than 5 (1<5) you round down making the nearest billion 7

8 0

3 years ago

Read 2 more answers