4 1/2 + 1 3/5in simplest form
1 answer:
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2(b-5)+7b-4
Solve 2(b-5) to get 2b-10
Combine your like terms 2b-10+7b-4
Solve 2b+7b to get 9b
Solve -10+(-4) to get -14
So your answer is
9b-14
Solve 2(b-5) to get 2b-10
Combine your like terms 2b-10+7b-4
Solve 2b+7b to get 9b
Solve -10+(-4) to get -14
So your answer is
9b-14
Answer:
B :- 15
Step-by-step explanation:
Given:
A package of red rose contains = 3 pieces
A package of white rose contains = 5 pieces
If an equal number of red and white roses are wanted to make bouquets, what is the minimum number of each that can be purchased ?
Solution:
As here given that there are two types of package of roses, red roses come 3 pieces to each packet and white roses come 5 pieces to each packet and we have to find equal minimum number of red roses as well as white roses to be purchased, we will simply find the Lowest common multiple of 3 and 5.
Multiples of 3 :- 3, 6, 9,12, 15, 18, 21, 24
Multiples of 5 :- 5, 10, 15, 20, 25
<em>Lowest common multiple is 15, that means </em><em>15 is the minimum number of pieces of each that can be purchased to make bouquets.</em>
And number of packets of red rose have to purchase = 3 <em><u>5</u></em> = 15, 5 packages.
And number of packets of white rose have to purchase = 5 <em><u>3</u></em> = 15 , 3 packages.