2 years ago

Find the quadratic function that has roots of -9 and 3 and a vertex of (-3,-36)

1 answer:

6 0

Y=(x+9)(x-3)+c
∵(-3,-36)lies on it.
-36=(-3+9)(-3-3)+c
-36=(-6)(-6)+c
-36=36+c
c=-36-36=-72
y=(x-9)(x+3)-72
y=x^2+3x-9x-27-72
y=x^2-6x-99

You might be interested in

faust18 [17]

Answer:

C.8/27

Step-by-step explanation:

4 0

1 year ago

mart [117]

Answer:

Angle 1 is 134 and Angle 2 is 46

5 0

2 years ago

diamong [38]

9x + 4 = 58
9x = 54
x = 6

The number is 6.

4 0

3 years ago

stiv31 [10]

$7x^{2} +33x-10=0$

$\implies 7x^{2} +35x-2x-10=0\\\implies7x(x+5)-2(x+5)=0\\\implies (7x-2)(x+5)=0$

$7x - 2 = 0\\\implies \boxed{\bold{x = \frac{2}{7} }}$

$x+5=0\\\implies \boxed{\bold{x=-5}}$

6 0

2 years ago

nikdorinn [45]

2/15+3/15=5/15 5 can go into both 5/5=1 and 15/5=3 which means
=1/3 is the answer

7 0

3 years ago