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stepan [7]
3 years ago
12

Find the midpoint of points A(9,9) and B(2,-1)

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

4 11/2

Step-by-step explanation:(X₁, Y₁) is the coordinates of the 1st point and (X₂, Y₂) is the coordinates of the 2nd point.

Using the formula above,.

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3 years ago
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Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
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let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
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let me tell you firstly i am juat writing this

Step-by-step explanation:

for absolutely no rwason whatsoevwr lol

ao ywah get some hwlp from a pro

3 0
3 years ago
(x - 1)(x + 5) = x² + 4x – 2<br><br> Step by step if possible please
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solve or simplify? if solve, what is x

Step-by-step explanation:

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3 years ago
This is a picture of a small sumu
Deffense [45]

Answer:

C

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