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aliina [53]
3 years ago
10

What is the answer to this 4(x+8)-4=34-2x

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0

Answer:

x =1

Step-by-step explanation:

4(x+8)-4=34-2x

Distribute the 4

4x+32 -4 =34 -2x

Combine like terms

4x +28 = 34 -2x

Add 2x to each side

4x+2x +28 = 34 -2x+2x

6x+28=34

Subtract 28 from each side

6x+28-28 = 34-28

6x = 6

6x/6 = 6/6

x =1

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In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

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3 years ago
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oksano4ka [1.4K]

Answer:

that correct answer is D, Substitute the coordinates x and y-value in the equation, (12 is the x-value, 10 is the y-value). 10 is not equal to 22 + 12, so the correct answer is D.

Hope this helps!

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vivado [14]
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3 years ago
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Can someone help me and explain how you did it?
Feliz [49]

Answer:

slope: -3/5

y-intercept: (0, 4)

slope-intercept form: y = -3/5x + 4

Step-by-step explanation:

<h3><u>Finding the slope</u></h3>

To find the slope of this line, you would take two points from the table and substitute their coordinates into the slope formula.

Slope formula: \frac{y_2-y_1}{x_2-x_1}

I'm going to use the points (0, 4) and (5, 1). You can really use any point from the table. Substitute these points into the formula to find the slope.

(0, 4), (5, 1) → \frac{1-4}{5-0} \rightarrow \frac{-3}{5}

This means the slope of the line is -3/5.

<h3><u>Finding the y-intercept</u></h3>

The y-intercept will always have the value of x be 0 (so the point is solely on the y-axis), so by looking at the table we can see that the y-intercept is at (0, 4).

<h3><u>Finding the slope-intercept form</u></h3>

Since we have the slope and a point of the line, we must use point-slope form to find the equation of the line in slope-intercept form. Substitute in the point (0, 4) --you could use any point from the table-- and the slope -3/5 into the point-slope form equation.

point-slope form: y - y1 = m(x - x1) --you'll be substituting the point coordinates and slope into y1, x1, and m.

y - (4) = -3/5(x - (0))

Simplify.

y - 4 = -3/5x

Add 4 to both sides.

y = -3/5x + 4 is the equation of the line in slope-intercept form (you have both the slope and the y-intercept in this form).

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