20-3h=2=>3h=20-2=18=>h=18/3=6
Use X1+X2 / 2, Y1+Y2 / 2
-3 + 2 / 2 , -5 + 7 / 2
-1 / 2 , 2/2
(-1/2, 1)
I think this is correct... I know you use the top formula
The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
Hello here is a solution :
<span> the radius of the circle is OA A(5;-12) and O (0;0)
OA= </span><span> square root ((5-0)² + (-12-0)²)
</span> = <span> square root (25+144)
</span> = <span> square root(169)
</span> OA = 13
Answer: Idek if that's a question
Step-by-step explanation: