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Dvinal [7]
2 years ago
10

Can I have help with the problem in the picture pls​

Mathematics
1 answer:
Bumek [7]2 years ago
8 0
A is the correct answer !
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A jar contains 18 red marbles 14 green marbels and 20 blue marbles a marble was selected at random the color was recorded and th
muminat

The "relative frequency" is

         (number of times a blue marble came out)
divided by
         (total number of trials before everybody got bored and quit) .

-- The relative frequency of blue was  (20/60)  =  (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)

-- The relative frequency of green was  (18/60)  =  30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)

-- The relative frequency of red was  (22/60)  =  (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)
3 0
3 years ago
Prove that the difference between a two-digit number and the product of its digits will always be a 2 digit number.
slamgirl [31]

Step-by-step explanation:

Let the two-digit number is xy

<u>This can be written as:</u>

  • 10x + y, where 1 ≤ x ≤ 9 and 0 ≤ y ≤ 9

<u>The difference between the number and product of its digits is:</u>

  • d = 10x + y - xy

<u>Rewrite this as below:</u>

d = 10x - xy + y - 10 + 10 =

     x(10 - y) - (10 - y) + 10 =

     (x - 1)(10 - y) + 10

<u>We see that:</u>

  • 0 ≤ x - 1 ≤ 8 according to the condition given above
  • 1 ≤ 10 - y ≤ 10 again according to the condition given above

<u>The value of d is then:</u>

  • 0 + 10 ≤ d ≤ 8*10 + 10
  • 10 ≤ d ≤ 90
<h3>Proved</h3>
7 0
2 years ago
Read 2 more answers
The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app
AfilCa [17]

Answer:

Q(t) = 4.5(1.013)^{t}

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that Q(0) = 4.5, r = 0.013

So

Q(t) = Q(0)(1+r)^{t}

Q(t) = 4.5(1.013)^{t}

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

Q(t) = 4.5(1.013)^{t}

Q(39) = 4.5(1.013)^{39} = 7.45

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0
3 years ago
A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)
klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt

= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}

= 330.45 - 109.72

= 220.7333

Answer: 221

3 0
3 years ago
Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a
Arisa [49]

Answer:

<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>

Step-by-step explanation:

Let, the specific heat of the container is x calories/gram-degree C.

The container and water gains (18 - 15) = 3 degrees C.

Hence, the transfer of heat is 3(18.1\times1000\times1) + 3(3.77x\times1000).

The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.

Hence, the transfer of heat is 144\times 1.45\times1000x.

As per the given conditions,

3(18.1\times1000) + 3(3.77x\times1000) = 144\times1.45\times1000x\\54.3 + 11.31x = 208.8x\\197.49x = 54.3\\x = 0.274951.

6 0
3 years ago
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