2 years ago

Solve the equation. identify any extraneous solutions. x=√6x+7

1 answer:

3 0

In order to solve the equation we first need to put the condition:
6x+7>=0
x>= -7/6

We square the equation:
x^2=6x+7
x^2-6x-7=0
x^2+x-7x-7=0
x(x+1)-7(x+1)=0
(x-7)(x+1)=0
x1=7
x2=1

Both solutions meet the condition.

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So we will break 64 up.

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