Answer:
3 pounds of peanuts and 2 pounds of cashews
Step-by-step explanation:
Let x be the pounds of peanuts and y be the pounds of cashews
Greta wants to make 5 pounds of a nut mix using peanuts and cashews.
So, 
----- A
Cost of 1 pound of peanuts = $4
Cost of x pounds of peanuts = 4x
Cost of 1 pound of cashews = $9
Cost of y pounds of cashews = 9y
Her budget requires the mixture to cost her $6 per pound
So, cost of mixture of x pounds of peanuts and y pounds of cashews is 6(x+y)
So, 
--- B
Plot A and B
---Blue
---Green
Refer the attached figure
Intersection point = (x,y)=(3,2)
Hence she should use 3 pounds of peanuts and 2 pounds of cashews
Answer:
40z + 5
Step-by-step explanation:
I'm assuming you need to factor 32z + 4 + 8z + 3 - 4 + 2
- 32z + 8z ( since they both have the same variable ) = 40z
- 4 + 3 - 4 + 2 ( since they have to variables ) = 5
Hope this helped
Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of is
Generally since the sample proportion is not given we will assume it to be
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=>
Generally the margin of error is mathematically represented as
Generally if the level of confidence increases, the critical value of 
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
Female students that participate: 51
male students that don’t: 30
