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Vitek1552 [10]
4 years ago
13

Simplify.Enter your answer, in simplest form, (in the boxes).

Mathematics
1 answer:
zepelin [54]4 years ago
5 0

Answer:

1/4

Step-by-step explanation:


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the sum of the measures of the interior angels of a convex polygon is 3240 classify the polygon by the number of sides
Ipatiy [6.2K]

Answer:

20-gon

Step-by-step explanation:

First we start with the formula  to find what the sum of angles will be if we know the number of sides.  


S=(n-2)*180 where S is the sum of angles and n is the number of sides.


Normally you'd plug in n to find S, but you can do the opposite too.


3240=(n-2)*180


Let me know if you need help working it from here.  

5 0
3 years ago
50<br> Σ (4n - 1) = [? ]<br> 1
Kay [80]

Answer:

5050

Step-by-step explanation:

3 0
3 years ago
Y=-7 + 2x how to graph
blondinia [14]
I know for 2x you would go up 2 over 1 but I don’t know about -7?? Maybe down
8 0
3 years ago
Devide<br> X^3+x^2+3x-4 by x^2+2x+1
lyudmila [28]

Answer:

x-1+\frac{4x-3}{x^2+2x+1}

Step-by-step explanation:

6 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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