Simplify.Enter your answer, in simplest form, (in the boxes).
1 answer:
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The distance between two points can be calculated using the following formula:
distance = sqrt [ (x2-x1)^2 + (y2-y1)^2]
Now, we are given the two points (5,4) and (1,-2)
Substitute with the given points in the above equation to get the distance as follows:
distance = sqrt [(1-5)^2 + (-2-4)^2]
distance = sqrt [16+36] = sqrt[52]
distance = 2√13 = 7.2111 units
distance = sqrt [ (x2-x1)^2 + (y2-y1)^2]
Now, we are given the two points (5,4) and (1,-2)
Substitute with the given points in the above equation to get the distance as follows:
distance = sqrt [(1-5)^2 + (-2-4)^2]
distance = sqrt [16+36] = sqrt[52]
distance = 2√13 = 7.2111 units
Answer:
In case (a) car makes 105° turn.
In case (b) car makes 75° turn.
In case (c) car makes 105° turn.
Step-by-step explanation:
Figure is redrawn To explain properly (in attachment)
Given : streets are parallel means ║
,
AB - 4th street , CD - 3rd street and XY - King Ave.
∠XLA = 75°
To find : (a) ∠XLB
(b) ∠LMD (left onto 3rd streat means left of car)
(c) ∠YMD (right means right side of car)
∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠XLB + 75° = 180°
∠XLB = 180 - 75
∠XLB = 105°
∴ In case (a) car makes 105° turn.
∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)
∠LMD = 75°
∴ In case (b) car makes 75° turn.
∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠YMD + 75° = 180°
∠YMD = 180 - 75
∠YMD = 105°
∴In case (c) car makes 105° turn.
