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nevsk [136]
3 years ago
15

1.) Jessica went deep sea diving. She makes the first stop on her descent at 25 meters below the surface of the water. From that

point she dives down further, stopping every 5 meters. If she makes 4 additional stops,which number represents her position, relative to the surface of the water?
Mathematics
1 answer:
Monica [59]3 years ago
6 0

Answer:

\boxed{\text{-45 m}}

Step-by-step explanation:

The surface of the water is at 0 m. Heights above the surface are positive and depths below the surface are negative.

\begin{array}{cc}\textbf{Stop} & \textbf{Change in Depth/m} \\1 & -25 \\2 & -5 \\3 & -5 \\4 & -5 \\5 & -5 \\\text{TOTAL DEPTH =} & \mathbf{-45} \\\end{array}\\\text{Jessica's depth relative to the surface of the water is $\boxed{\textbf{-45 m}}$}

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The client is to receive cyclophosphamide (Cytoxan) 50 mg/kg intravenously in divided doses over 5 days. The client weighs 176 p
marishachu [46]

Answer:

800 mg

Step-by-step explanation:

As the excerpt states that the client weights 176 pounds and is to receive cyclophosphamide (Cytoxan) 50 mg/kg, we have to convert 176 pounds to kg:

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  x   ←  176 pounds

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The flying squirrel of eastern Texas can drop from a height of 60 feet. A function that approximates this drop is h = −16t 2 + 6
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Step-by-step explanation:

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3 years ago
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
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