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Sergeeva-Olga [200]
3 years ago
5

A certain rectangle is 5 times as long as it is wide. Suppose the length and width are both tripled. The perimeter of the second

rectangle is how many times as large as the perimeter of the first rectangle?
Mathematics
1 answer:
astraxan [27]3 years ago
3 0
It is tripled as well. You are tripling every distance and thus tripling the sum of the distances as well. 
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How do you find the area of this composite figure?
Illusion [34]
If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid   \bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad 
\begin{cases}
h=height\\
a,b=\textit{parallel sides or bases}
\end{cases}

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

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3 years ago
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____ [38]

Answer:

-1

Step-by-step explanation:

This all comes down to the substitution. I am assuming that (4x2) is meant to be 4x^2 so I will solve as that.

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Jack and his two friends each ordered a small pizza, Jack ate 7/8 of his pizza, Luis ate 3/4 of his pizza, Tyrone ate 1/2 of his
Thepotemich [5.8K]
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3 0
2 years ago
Read 2 more answers
If all the sides of a triangle get 2 times as big, how much does the area change?
KIM [24]

Answer:

Step-by-step explanation:

area becomes 2²=4  times.

4 0
3 years ago
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