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kvasek [131]
3 years ago
6

Which of these physical factors most shapes the characteristics of a ecosystem? A) soil type B) longitude C) temperature and rai

nfall D) air circulation patterns
Biology
2 answers:
Nezavi [6.7K]3 years ago
6 0
I believe it is temperature or rainfall. All of the factors are improtant but temperature comes first, cuz the temperature can also determine the air, and soil doesn't make a difference. Longitude doesn't have to do with an ecosystem.
Arada [10]3 years ago
5 0
C.
All others are irrelevant
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Plants and animals that live in estuaries face a dilemma in maintaining water balance inside their cells. During high tide they
jok3333 [9.3K]

Answer:

The correct answer is "a hypertonic solution".

Explanation:

Seawater is the most clear example of a hypertonic solution in nature. The concentration of ions in seawater are far more superior than the concentration of ions inside a plant or an animal cell, since seawater have an osmolarity of about 1000 mOsm/l. Therefore, at high tide a plant or animal cell will be in a hypertonic solution, and the cells must have adaptions to avoid cell shrinking and dead.

6 0
2 years ago
Janine’s hands are larger than her father’s hands. Which explanation can account for the difference in hand size between father
aleksandrvk [35]

Answer:

I think it is either D or A

Explanation:

7 0
3 years ago
Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some
Sphinxa [80]

Answer and Explanation:

<em><u>The number of observed individuals</u></em>:

  • AA 42
  • AG 24
  • GG 21

<u><em>Total number of individuals, N</em></u>= 87 = 42 + 24 + 21

<u><em>Allelic frequencies</em></u>:

  • f(p) = (2 x AA + AG)/ 2 x N

       f (p)= (2 x 42 + 24) /2 x 87

       f (p) = (84 + 24) / 174

       f (p)= 108 / 174

      f (p) = 0.62

  • f (q) = (2 x GG + AG)/2 x N

        f (q) = (2 x 21 + 24 )/2 x 87

        f (q) = (42 + 24)/ 174

        f (q) = 66/174

        f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

<em><u>The expected genotypic frequency:</u></em>

  • F (AA)= 0.62 ² = 0.3844
  • F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712
  • F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

<u><em>The number of expected individuals</em></u>:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

<u><em>Total number of expected individuals</em></u> = 33.44 + 40.99 + 12.563 = 87

<u><em>Chi square</em></u>= sum (O-E)²/E

  • AA= (O-E)² /E

        AA=(42 - 33.44) ² / 33.44

        AA= 2.2

  • AB= (O-E)² /E      

        AB= (24 - 40.99)²/ 40.99

        AB=7.04

  • BB=(O-E)² /E

        BB= (21-12.563)²/12.563

        BB= 5.66

<u><em>Chi square</em></u>= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

<u><em>Degrees of freedom</em></u> = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

5 0
3 years ago
Describe how the shape of the insulin receptor allows glucose to get into the cell
Aloiza [94]

Type 1 Diabetic here! I can help!! so basically the receptor for insulin is a large protein that binds to insulin and passes its message into the cell. It has several functional parts. Two copies of the protein chains come together on the outside of the cell to form the receptor site that binds to insulin.

I hope this helped :)

6 0
3 years ago
Around 350 BC the famous philosopher Aristotle claimed that all living things should be classified into two categories: "Blood"
Paha777 [63]
<span>Question B) the development of the microscope Eliminate.
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3 years ago
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