Answer:
f(x) is continuous on the interval [0, 1], f(0) = <u>-2</u> , and f(1) = <u>1.718</u> . Since f(0) < 0 < f(1) , there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation ex = 3 − 2x, in the interval (0, 1)
Step-by-step explanation:
From the question we are told that
The equation is
The interval is [0, 1]
Generally f(0) is
=>
=>
Generally f(1) is
From the value we see that at x = 0 , f(0) = -2 which is below the x-axis
and the at x = 1 , f(1) = 1.718 which is above the x-axis
Now the according to Intermediate Value Theorem , given the condition stated above, there will exist a root c in the interval such that
f(c) = 0
Answer:
8
Step-by-step explanation:
To do this problem, you take 16 and take 50% away, or divide by two. This will give you 8
Answer:
42
Step-by-step explanation:
7x6
Since y = 1/2x + 3
X - 2(1/2x + 3), x/1 - 2x/2 -6/2 = x+3
Or x-x-3=0 which equals -3 so it is inconsistent since it's not dependable :)