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Novosadov [1.4K]
3 years ago
11

An artist mixes yellow an blue paint to make the perfect shade of green. she uses 2 ounces of blue paint for every 7 ounces of y

ellow. How many ounces of yellow will the artists need to add of 12 ounces of blue?​
Mathematics
2 answers:
Alex Ar [27]3 years ago
6 0

Answer:

42

Step-by-step explanation:

2 times 6 is 12

So 7 times 6 is 42 ounces

sweet-ann [11.9K]3 years ago
4 0

Hello!

The artist will need 42 ounces of yellow paint

If you count each yellow corresponding to the blue its pretty simple

7 = 2

14 = 4

21 = 6

28 = 8

35 = 10

42 = 12

So its basicaly adding both numbers up until you reach 12, which will then answer how much yellow you would need

Hope this helps!

Please consider Brainliest!

Have a great day!

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Answer:

\$17,500

Step-by-step explanation:

Let

x----> that month's sales

y----> October earnings

we know that

8\%=8/100=0.08

y=0.08x+1,400 -----> equation A

y=2,800 -----> equation B

Equate equation A and equation B and solve for x

2,800=0.08x+1,400

0.08x=2,800-1,400

x=1,400/0.08

x=\$17,500

3 0
3 years ago
Darren is finding the equation in the form y = m x b for a trend line that passes through the points (2, 18) and (–3, 8). Which
Lera25 [3.4K]
B is consider to be the y-intercept. If you plot those two points and draw a line connecting the two. The line would go through (0,14). Making 14 the y-intercept and the correct answer.
5 0
2 years ago
The number of right-handed students in a math class is nine times the number of left-handed students. The total number of studen
nirvana33 [79]
R - Right Handed 
L - Left Handed 

R = 9L ( the number of right handed kids is equal to having 9*number of left handed kids) 
9L + L = 30  ( since total number of people in class is 30) 
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L = 3 

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Hope this helped!
5 0
3 years ago
12 y − 18 6 = 4 y + 3 12 y - 18 6 = 4 y + 3
Burka [1]

Step-by-step explanation:

I didn't understood thr question and I'm pretty sure that u made a mistake while writing it

3 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
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