Ask question

Ask question

All categories

2 years ago

9

Solve for a. ab + c = d

1 answer:

Inga [223]2 years ago

7 0

It is the first one I believe

You might be interested in

What is 700÷80 and with the remainder thanks

Viefleur [7K]

Answer:

640 R = 60

Explain Your Answer:

7 0

3 years ago

Can someone help me please?

morpeh [17]

Heya bro!!

------------------------------------

If uh r asking about scientific notification then x must be in lowest form but decimal point is after 1.

So correct answer is 1.04 * 10^2 .

If uh wanna check multiply it.. Uh will get 104.

Hope it helps uh!

5 0

3 years ago

A(n)_____is a mathematical sentence that compares expressions that are equal

RUDIKE [14]

Answer:

equation

Step-by-step explanation:

plz mark brainliest

4 0

2 years ago

The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent.Find the single reduction the

Evgen [1.6K]

Answer:

40% . The single reduction together is 40%.

Step-by-step explanation:

Let the bicycle cost is x before reduced price.

First 25% is reduced and again 20% further reduced.

Let the single reduction is y% if the two reduction together are equal.

Solution,

Case .1

reduction cost $=x\times 25%$ %

$=x\times 25/100$

$=x/4$

The cost of bicycle after reduction of 25% is

$=x-x/4=3x/4$

cost of reduction further reduction of 20% $=3x/4\times 20$ %

$=3x\times 20/(4\times 100)$

$=3x/20$

The new cost of bicycle is further reduction of 20% is

$=3x/4-3x/20$

$=\left ( 15x-3x \right )/20$

$=12x/20=3x/5$

Case.2

if single reduction is done new cost of cycle is equal

$x-x\times y$ %= $3x/5$

$x\left ( 1-y/100 \right )=3x/5$

$\left ( 100-y \right )/100=3/5$

$100-y=60$

$y=40$ %

single reduction of a cycle is 40%

8 0

3 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

7 0

3 years ago