Question

Suppose the round-trip airfare between Boston and Orlando follows the normal probability distribution with a mean of $387.20 and a standard deviation of $68.50. What is the probability that a randomly selected airfare between Boston and San Francisco will be less than $300

Answer 1

Answer: P < 300 = 0.102

Step-by-step explanation:

Suppose the round-trip airfare between Boston and Orlando follows the normal probability distribution, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the round-trip airfare between Boston and Orlando.

µ = mean

σ = standard deviation

From the information given,

µ = $387.20

σ = $68.50

The probability that a randomly selected airfare between Boston and San Francisco will be less than $300 is expressed as

P < 300

For x = 300,

z = (300 - 387.20)/68.5 = - 1.27

Looking at the normal distribution table, the probability corresponding to the z score is 0.102