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4 years ago

11

Write a word problem that can be solved by ordering three decimals to thousandths include a solution

1 answer:

Mariana [72]4 years ago

8 0

<span>If I have a bolt that has a diameter of 1.125 inches and a hole that's 1.300 inches with a tolerance of +/- 0.025 inches, what's the larger even tolerance I can have on the bolt to ensure it will pass through the hole? Answer: +/- 0.150 inches.</span>

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10-9=110x7 what symbol will make this equation equal

irina [24]

< that is the anwer to the prob

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4 years ago

Which is more, 1 quart or 3 cups?

Andrew [12]

Answer:

1 quart is more.

Step-by-step explanation:

1 quart =4cups so 1 quart is more.

4 0

3 years ago

Read 2 more answers

Pls help ill give brainliest

Mashcka [7]

Answer:

19 hours

Step-by-step explanation:

2.83333/.3= 19.44

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3 years ago

Determine the dimensions of a rectangular solid (with a square base) with maximum volume if its surface area is 181.5 square cen

3241004551 [841]

Answer:

The base and height of the solid is 5.5cm

<em></em>

Step-by-step explanation:

Given

$Surface\ Area = 181.5cm^2$

Required

Determine the dimensions that maximizes the volume

Let the base dimension be x and the height be h

The volume is calculated as:

$Volume =x^2 * h$

$Volume =x^2h$

181.5 =x^2h

The surface area (S) is calculated as this:

$S = 2(x^2 + xh + xh)$

$S = 2(x^2 + 2xh)$

$S = 2x^2 + 4xh$

Substitute 181.5 for S

$181.5 = 2x^2 + 4xh$

Make h the subject:

$4xh = 181.5 - 2x^2$

$h = \frac{181.5 - 2x^2}{4x}$

Substitute $h = \frac{181.5 - 2x^2}{4x}$ in $Volume =x^2h$

$V = x^2(\frac{181.5 - 2x^2}{4x})$

$V = x(\frac{181.5 - 2x^2}{4})$

$V = \frac{1}{4}(x)(181.5 - 2x^2)$

$V = \frac{181.5x}{4} - \frac{2x^3}{4}$

$V = \frac{181.5x}{4} - \frac{x^3}{2}$

To get the maximum, we differentiate V with respect to t and set the differentiation to 0

$dV = \frac{181.5}{4} - \frac{3x^2}{2}$

Set to 0

$0 = \frac{181.5}{4} - \frac{3x^2}{2}$

$\frac{3x^2}{2} = \frac{181.5}{4}$

Multiply through by 4

$4 * \frac{3x^2}{2} = \frac{181.5}{4} * 4$

$2*3x^2 = 181.5$

$6x^2 = 181.5$

$x^2 = \frac{181.5}{6}$

$x^2 = 30.25$

$x = \sqrt{30.25$

$x = 5.5$

Recall that:

$h = \frac{181.5 - 2x^2}{4x}$

$h = \frac{181.5 - 2 * 5.5^2}{4 * 5.5}$

$h = \frac{181.5 - 60.5}{22}$

$h = \frac{121}{22}$

$h = 5.5$

So, we have:

$h = 5.5$

$x = 5.5$

<em>Hence, the base and height of the solid is 5.5cm</em>

7 0

3 years ago

What are the x- and y-intercepts of the line 6x−y=10?

Elena-2011 [213]

Step-by-step explanation:

This equation is in Standard Form. To find the x and y intercepts, it is easier to convert it to slope-intercept form, or y = mx + b.

6x - y = 10

-y = -6x + 10

y = 6x - 10

In slope-interecept form, you can see that the y-int, b, is -10, the constant. To find x, set y to zero.

0 = 6x - 10

10 = 6x

10/6 = x

5/3 = x

3 0

3 years ago