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pashok25 [27]
3 years ago
12

During a thunderstorm, a lightning "bolt" carries current between a cloud and the ground below.

Physics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Explanation:

It is given that,

Total charge carried in a bolt, q = 31 C

Time taken, t=2.4\ ms=2.4\times 10^{-3}\ s

Let I is the magnitude of current flowing in a bolt. The total charge flowing per unit time is called electric current. Mathematically, it is given by :

I=\dfrac{q}{t}

I=\dfrac{31\ C}{2.4\times 10^{-3}\ s}

I = 12916.66 A

Let n is the number of electrons. According to the quantization of charges,

q = ne  

n=\dfrac{q}{e}

e is the charge on electron

n=\dfrac{31}{1.6\times 10^{-19}}

n=1.93\times 10^{20}

Hence, this is the required solution.

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Will mark Brainliest!!
Ilya [14]

Answer: 600 m

Explanation:

Speed V is defined as the distance traveled d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=343 m/s \approx 300 m/s is the speed of sound  

t=2 s the time you hear the thunder after you see the flash of lightning  

We need to find the distance at which you are from the lightning strike:  

300 m/s=\frac{d}{2 s}  

Finding d:  

d=(300 m/s)(2 s)  

Finally:  

d=600 m

5 0
3 years ago
7
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7 0
2 years ago
In which activity is no work done?
sleet_krkn [62]
The answer is B because you are not using force or energy as if you were if you were to lift or push something.
3 0
4 years ago
Read 2 more answers
What is the work Sarah,60kg does against gravity is she goes up a 4m high stairwell in 3 seconds?
ladessa [460]
Work can be obtained from the following expression

W = F*d

Where F is the force (In this case the force it takes to lift Sarah, which is mass*gravity)

And d is the distance traveled.

W = 60kg*9.8m/s^2 * 4m = 2352 Joules 
3 0
3 years ago
In 1865, Jules Verne proposed sending men to the Moon by firing a space capsule from a 220-m-long cannon with final speed of 10.
Sidana [21]

Answer:

The unrealistically large acceleration experienced by the space travelers during their launch is 2.7 x 10⁵ m/s².

How many times stronger than gravity is this force? 2.79 x 10⁴ g.

Explanation:

given information:

s = 220 m

final speed, vf = 10.97 km/s = 10970 m/s

g = 9.8 m/s²

he unrealistically large acceleration experienced by the space travelers during their launch

vf² = v₀²+2as, v₀ = 0

vf² = 2as

a =vf²/2s

  = (10970)²/(2x220)

  = 2.7 x 10⁵ m/s²

Compare your answer with the free-fall acceleration

a/g = 2.7 x 10⁵/9.8

a/g = 2.79 x 10⁴

a = 2.79 x 10⁴ g

7 0
3 years ago
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