<span>Step 1 -- determine the acceleration of the 200-g block after bullet hits it
a = (coeff of friction) * g
g = acceleration due to gravity = 9.8 m/sec^2 (constant)
a = 0.400*9.8
a = 3.92 m/sec^2
Step 2 -- determine the speed of the block after the bullet hits it
Vf^2 - Vb^2 = 2(a)(s)
where
Vf = final velocity = 0 (since it will stop)
Vb = velocity of block after bullet hits it
a = -3.92 m/sec^2
s = stopping distance = 8 m (given)
Substituting values,
0 - Vb^2 = 2(-3.92)(8)
Vb^2 = 62.72
Vb = 7.92 m/sec.
M1V1 + M2V2 = (M1 + M2)Vb
where
M1 = mass of the bullet = 10 g (given) = 0.010 kg.
V1 = velocity of bullet before impact
M2 = mass of block = 200 g (given) = 0.2 kg.
V2 = initial velocity of block = 0
Vb = 7.92 m/sec
Substituting values,
0.010(V1) + 0.2(0) = (0.010 + 0.2)(7.92)
Solving for V1,
V1 = 166.32 m/sec.
Therefore the answer is (B) 166 m/s!</span>
The amount of work done by the person is equal to 120 Joules.
<u>Given the following data:</u>
- Displacement = 15 meters.
To calculate the amount of work done by the person at a total height of 2 meters:
<h3>How to calculate work done.</h3>
In Science, work done is calculated by multiplying force and the displacement experienced by an object.
Mathematically, work done is given by the formula:
Substituting the given parameters into the formula, we have;
Work done = 120 Joules.
Read more on work done here: brainly.com/question/22599382
Answer:
Explanation:
A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. ... The name is derived from the Pythagorean theorem, stating that every right triangle has side lengths satisfying the formula a2 + b2 = c2; thus, Pythagorean triples describe the three integer side lengths of a right triangle.
Answer:3.98cm
Explanation:
given data
mass of object
=0.5kg
intial extension=5 cm
elevator acceleration=2 m/
From FBD of intial position
Kx=mg
K=
k=98.1 N/m
From FBD of second situation
mg-k
=ma
k=m(g-a)
=
=3.98cm
