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3 years ago

1. Consider a 1000 kg car rounding a curve on a flat road of radius 50 m at a speed of

Physics

1 answer:

raketka [301]3 years ago

6 0

Answer:

The car will make the turn perfectly

Explanation:

Given that the centripetal force= mv^2/r

M= mass of the car

v = speed of the car

r= radius

Hence;

F = 1000 × (14)^2/50

F= 3920 N

The frictional force = μmg

μ = coefficient of static friction

m= mass

g = acceleration due to gravity

Frictional force= 0.6 × 1000× 10

Frictional force = 6000 N

The car will not skid off the curve because the frictional force is greater than the centripetal force.

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A 5.0-newton force could have perpendicular components of

tino4ka555 [31]

Answer:

It can have many set of perpendicular component but the most important one is 3 AND 4

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE 

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3 years ago

A 1,800-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.00 m before coming into contact

Jobisdone [24]

Answer:

average force = 385,140 N

Explanation:

from the question we are given the following

mass (m) = 1800 kg

distance of fall (d) = 3 m

driven distance (l) = 14.4 cm = 0.144 m

acceleration due to gravity (g) = 9.8 m/s^{2}

work done = average force x driven distance.....equation 1

and

work done = change in kinetic energy + change in potential energy

work done = (0.5 x m x (v^{2} - u^{2})) + (m x g x (-d-l))

Initial velocity (u) and final velocity (v) are zero because the pile driver is it rest before it moves to hit the pile and after hitting the pile.
The changes in length for the potential energy are negative because the pile moves downward

we now have work done = (m x g x (-d-l))...equation 2

now equating the two equations for work done we have

average force x driven distance = (m x g x (-d-l))

average force x 0.144 = 1800 x 9.8 x (-3-0.144)

average force = (1800 x 9.8 x (-3-0.144)) ÷ 0.144

average force = 385,140 N

3 0

3 years ago

PLZ HELP DUE IN 10MIN!!!!!!!!!The temperature of the water vapor (H2O) inside a pressure cooker increased from 295 K to 395 K. A

madreJ [45]

Did you ever figure it out, bc now I need it lol.

3 0

3 years ago

What is a purpose in flexibility

icang [17]

Answer:

To prevent from getting injured.

8 0

3 years ago

Read 2 more answers

You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on

Zielflug [23.3K]

Answer:

4.3 cm

Explanation:

We are given that

Width,d=70.3 $\mu m=70.3\times10^{-6} m$

$1\mu m=10^{-6} m$

Wavelength, $\lambda=719 nm=719\times 10^{-9} m$

$1nm=10^{-9} m$

$r=2.11 m$

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

$sin\theta_{min}\approx \theta=\frac{\lambda}{d}=\frac{719\times 10^{-9}}{70.3\times 10^{-6}}=0.0102 rad$

$y=r\theta=2.11\times 0.0102=0.0215 m$

The width of the pattern= $2y=2\times 0.0215=0.043 m=0.043\times 100=4.3 cm$

8 0

3 years ago