Answer:
1. 30°
2.90°
3. 12 units
Step-by-step explanation:
I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)
1.
The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.
2.
If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.
3.
Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.
Sorry if this is all dreadfully wrong, and I hope I helped you!
An example scenario is:
Anthony goes to the gym for <em>20</em> minutes on Monday. Every day he <em>multiplies</em> his gym time by <em>2</em>.
On the fifth day, he will spend spend 320 minutes in the gym.
The formula used to determine the 5th term is,
a5 = 20 x 2^(r -1)
where r is the common ratio equal to 2.
Answer:
3(7 + 4)2 − 24 ÷ 6 = 62
Step-by-step explanation:
3(7 + 4)2 − 24 ÷ 6 is the given expression.
Now, by the rule of BODMAS, where B = Bracket, O= of, D = divide,
M = multiplication, A = addition and S = subtraction
we try and solve the following expression in the same order.
Solving the bracket first, we get
3<u>(7 + 4)</u>2 − 24 ÷ 6 = 3(<u>11</u>)2 − 24 ÷ 6 =<u> 66</u> − 24 ÷ 6
Next, we solve divide,
66 − <u>24 ÷ 6</u> = 66 - <u>4</u>
Next, solving the subtraction, 66 - 4 = 62
Hence, 3(7 + 4)2 − 24 ÷ 6 = 62
Answer:
- 18x + 15y ≤ 300
- x ≥ 0; y ≥ 6
Step-by-step explanation:
Variables are defined in the problem statement.
18x +15y ≤ 300 . . . . total budget
y ≥ 6 . . . . . . . . . . . . minimum number of annuals
x ≥ 0 . . . . . number of perennials cannot be negative
This system of inequalities describes the situation.
-3 and 4......................
