Answer:
So the vaule of y is 7, 10 & 13
Step-by-step explanation:
Given that y = 3x+1 . So we can just substitute x-value into the equation :
Let x=2,
y = 3(2)+1
= 7
Let x=3,
y = 3(3)+1
= 10
Let x=4,
y = 3(4)+1
= 13
Answer:
The answer is below
Step-by-step explanation:
The volume of a box with a length of l, width of w and a height of h is given by the formula:
volume of the box = length * width * height = lwh
The volume of a cylinder with a height of h, and radius r is given by the formula:
volume of the cylinder = π * radius² * height = πr²h
Since the box and the cylinder have the same height and the cylinder is wide enough for the box to be placed inside, this means that the box has a volume greater than that of the cylinder. Hence:
If the box can take 8 cups, the cylinder would be able to take 10 cups.
Answer:
B 22
Step-by-step explanation:
The equation is option number c because someth = smth
Answer: ![1,270in^2](https://tex.z-dn.net/?f=1%2C270in%5E2)
Step-by-step explanation:
The surface area of a rectangle can be calculated with:
![Area_{rectangle}=lenght*width](https://tex.z-dn.net/?f=Area_%7Brectangle%7D%3Dlenght%2Awidth)
The surface area of a trapezoid can be calculated with:
![Area_{trapezoid}=\frac{height}{2}(Larger\ base+Smaller\ base)](https://tex.z-dn.net/?f=Area_%7Btrapezoid%7D%3D%5Cfrac%7Bheight%7D%7B2%7D%28Larger%5C%20base%2BSmaller%5C%20base%29)
Calculate the area of the base, wich is a rectangle:
![A_{1}=(34in)(15in)=510in^2](https://tex.z-dn.net/?f=A_%7B1%7D%3D%2834in%29%2815in%29%3D510in%5E2)
There are two equal rectangles, therefore, multiply the area of any of them by 2:
![A_{2}=2(15in)(13in)=390in^2](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2815in%29%2813in%29%3D390in%5E2)
Calculate the area of the other rectangle:
![A_{3}=(15in)(10in)=150in^2](https://tex.z-dn.net/?f=A_%7B3%7D%3D%2815in%29%2810in%29%3D150in%5E2)
There are two equal trapezoids, therefore, multiply the area of any of them by 2:
![A_4=\frac{2(5in)}{2}(34in+10in)=220in^2](https://tex.z-dn.net/?f=A_4%3D%5Cfrac%7B2%285in%29%7D%7B2%7D%2834in%2B10in%29%3D220in%5E2)
Therefore, the surface area will be the sum of all the areas calculated:
![SA=A_1+A_2+A_3+A_4\\\\SA=510in^2+390in^2+150in^2+220in^2\\\\SA=1,270in^2](https://tex.z-dn.net/?f=SA%3DA_1%2BA_2%2BA_3%2BA_4%5C%5C%5C%5CSA%3D510in%5E2%2B390in%5E2%2B150in%5E2%2B220in%5E2%5C%5C%5C%5CSA%3D1%2C270in%5E2)