The linear model of this case takes the form:
y = a(x-b) + k
<span>The cost of having a package delivered has a base fee of $9.70
this is "k" >>>>> k=9.7 (fixed amount of fee)
THEN
</span>
<span>Every pound over 5 lbs cost an additional $0.46 per pound
that means: 0.46(x-5)
in other words, if the package weighs foe example 9 pounds, then 9-5=4, it will cost 0.46*4 for these 4 extra pounds
Finally we have the linear form of this: C = 0.46 (W - 5) + 9.7
</span>
ANSWER
1. Multiply the fraction by 5/5 to get a denominator of 100 and then write the numerator as hundredths using a decimal point.
EXPLANATION
Renaldo wants to write
![\frac{3}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B20%7D%20)
as a decimal.
He needs a denominator of 100, so he can multiply by
![\frac{5}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B5%7D%20)
to obtain:
![\frac{3}{20} = \frac{3 \times 5}{20 \times 5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B20%7D%20%20%3D%20%20%5Cfrac%7B3%20%5Ctimes%205%7D%7B20%20%5Ctimes%205%7D%20)
This will be
![= \frac{15}{100}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B15%7D%7B100%7D%20)
He can now obtain the decimal equivalent as
![= 0.15](https://tex.z-dn.net/?f=%20%3D%200.15)
The correct choice is option 1.
Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.
Ann (A): A
Zoe (Z): A = Z - 12 → Z = 12 + A
Jim (J): A = J - 16 → J = 16 + A
A + Z + J = 154
(A) + (12 + A) + (16 + A) = 154
3A + 28 = 154
3A = 126
A = 42
Ann (A): A = 42
Zoe (Z): Z = 12 + A = 12 + 42 = 54
Jim (J): J = 16 + A = 16 + 42 = 58
Answer: Ann=42, Zoe=54, Jim=58
Answer:
The price of the cake is $24 and the price of the Pie is $15
Step-by-step explanation:
Given
<em>Represent price of Cake with C and Price of Pie with P</em>
![C = 9 + P](https://tex.z-dn.net/?f=C%20%3D%209%20%2B%20P)
Cakes sold = 8
Pies sold = 14
![Total = \$402](https://tex.z-dn.net/?f=Total%20%3D%20%5C%24402)
Required
Determine C and P
To represent the cakes and pies sold, we have the following expression
![8C + 14P = 402](https://tex.z-dn.net/?f=8C%20%2B%2014P%20%3D%20402)
Substitute 9 + P for C
![8(9+P) + 14P = 402](https://tex.z-dn.net/?f=8%289%2BP%29%20%2B%2014P%20%3D%20402)
Open the bracket
![72 + 8P + 14P = 402](https://tex.z-dn.net/?f=72%20%2B%208P%20%2B%2014P%20%3D%20402)
Collect Like Terms
![8P + 14P = 402 - 72](https://tex.z-dn.net/?f=8P%20%2B%2014P%20%3D%20402%20-%2072)
![22P= 330](https://tex.z-dn.net/?f=22P%3D%20330)
Divide both sides by 22
![P = \frac{330}{22}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B330%7D%7B22%7D)
![P = 15](https://tex.z-dn.net/?f=P%20%3D%2015)
Recall that
![C = 9 + P](https://tex.z-dn.net/?f=C%20%3D%209%20%2B%20P)
![C = 9 + 15](https://tex.z-dn.net/?f=C%20%3D%209%20%2B%2015)
![C = 24](https://tex.z-dn.net/?f=C%20%3D%2024)
<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>