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Svetlanka [38]
2 years ago
11

Which values are solutions to the inequality shown in the picture?

Mathematics
1 answer:
Olenka [21]2 years ago
4 0

Answer:

de

Step-by-step explanation:

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Harold has been hired as a salesman. He is paid a flat rate of $375 each week and earns an additional $14.25 commission for each
Andru [333]
The answer is
c. \: y = 14.25h + 375
5 0
3 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
2 years ago
Read 2 more answers
How many squares are in the circle below
Alinara [238K]

Answer:

66 squares are in the circle.

7 0
2 years ago
Read 2 more answers
You are dealt one card from a​ 52-card deck. find the probability that you are not dealt a two
Rina8888 [55]

There are 52 cards in a deck.

First we find the probability of drawing a 2

There are 4 cards that shows 2

Probability of drawing a 2 card fro 52 cards = 4 / 52

We know that P( not A) = 1 - P(A)

So the probability (not dealt a 2) = 1 - probability (dealt a 2)

= 1 - 4/52

= (52 - 4)/ 52 = 48/52

Now we simplify the fraction

48/ 52 = 12/13

Hence, the probability( not dealt a 2) = 12/13

7 0
3 years ago
PLEASE HELP ME AS SOON AS POSSIBLE!
mestny [16]

Answer:

2(c - 8) = 3

Hope this helps, thank you :) !!

4 0
2 years ago
Read 2 more answers
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