HELP QUICK PLS, For each of the figures, write Absolute Value equation in the form

Mathematics

2 answers:

ch4aika [34]3 years ago

8 0

D. In absolute value a negative and positive does not matter

igomit [66]3 years ago

8 0

Answer: b) |y-11|=6

d) |a-0|=1/2

Step-by-step explanation:

In the number line its y for b) and a for d) not x

How to solve b):

The equation is |y-c|=d

y=5,x=17

find the midpoint between those numbers. (17+5)/2=11

c=11, c is always the midpoint of the equation

|y-11|=d

for d, substatute y, y=5, y=17

|5-11|=6

|17-11|=6

d=6, thus your answer |y-11|=6

How to solve d)

Same thing

equation = |a-c|=d

a=1/2,a=-1/2

the midpoint of 1/2 and -1/2=0

c=0, |a-0|=d

substitue a, |1/2-0|=1/2 , |-1/2-0|=1/2, thus your answer |a-0|=1/2

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Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

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Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7709