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3 years ago

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A clothing store salesman had $5212 in total sales last month. He made $175 in commision. What is the commision as a percent of

the total monthly sales?

1 answer:

Elis [28]3 years ago

3 0

Divide the amount of commission made by the total sale, then multiply the decimal answer by 100 for the percent:

175 / 5212 = 0.03357

0.03357 * 100 = 3.357%

Round the answer as needed.

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coldgirl [10]

Answer:

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$A=4(3x)+4(-5)\\\\A=12x-20$

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2 years ago

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DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

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We split up the domain of integration into 10 subintervals,

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with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$

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Compare this to actual value of the integral, which is closer to 1967.

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shtirl [24]

Answer:

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Step-by-step explanation:

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3 years ago