The answer to the solution of this system of equations is (7, -4)
Answer:
8.94 if no rounding is necessary.
Step-by-step explanation:
Pythagorean Theorem. What we know is only one leg and the hypotenuse, sooo...
8² + b² = 12²
64 + b² = 144
Subtract 64 from both sides...
64 - 64 + b² = 144 - 64
b² = 80
= 8.94 if you're not rounding.
Answer:
x = 3/5, -3/5
Step-by-step explanation:
The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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Answer: 1/12 || 2x-1/2=2x-1/12
