Yes, not a equallateral but an issoceles
Answer: OPTION A.
Step-by-step explanation:
Given the following function:

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:

In this case:

Then, substituting values, you get:

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>
Answer:
Option C. 2x + 20 / x² + 6x – 40
Step-by-step explanation:
f(x) = x + 16 / x² + 6x – 40
g(x) = 1 / x + 10
To find f(x) + g(x), please refer to the attached photo.
#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.
Answer:
30n
Step-by-step explanation:
-24+54=30×n=30n
I needed 20 more letters so ya lol