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DedPeter [7]
3 years ago
15

Help it is so hard.And my teacher expects it done.

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0
If you can take a better picture of it I will be able to answer the questions for you
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Answers for he ones circles??
Contact [7]
1. 7x + 3 - 2x....x = 8
   7(8) + 3 - 2(8) = 56 + 3 - 16 = 43

4. 7 - (-2y) + y - 9....y = 6
     7 - (-2(6) + 6 - 9 = 7 + 12 + 6 - 9 = 16

7. -x + 8 + 7x - (-1).....x = -10
   -(-10) + 8 + 7(-10) + 1 = 10 + 8 - 70 + 1 = -51

10. 4x + 2y - x - 8....x = 1, y = 5
      4(1) + 2(5) - 1 - 8 = 4 + 10 - 9 = 5

13. 2x + 5y - 3x + (-8y)....x = -9, y = 9
      2(-9) + 5(9) - 3(-9) - 8(9) = -18 + 45 + 27 - 72 = -18


3 0
4 years ago
Pls help I need a good grade I’ll brainlest
ICE Princess25 [194]
Answers are in the photo below. Good luck.

7 0
3 years ago
Mary can read 10 pages in 20 minutes how fast can she read
Zanzabum

Answer:

Mary can read one page per two minutes.

Step-by-step explanation:

20 divided by 10 equals two

4 0
4 years ago
Read 2 more answers
PLEASE, PLEASE HELP WITH THIS SOON!
levacccp [35]

Answer:

12.08

Trust me

5 0
3 years ago
Read 2 more answers
Determime the intercepts of the line that passes through the following points. (-6,5);(-3,3);(0,1)
butalik [34]

well for a line, to get its slope all we need is two points, so let's use (-6, 5) and (0, 1), and get the equation of it.


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\qquad
(\stackrel{x_2}{0}~,~\stackrel{y_2}{1})
\\\\\\
slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-5}{0-(-6)}\implies \cfrac{1-5}{0+6}\implies -\cfrac{5}{6}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-5=-\cfrac{5}{6}[x-(-6)]\implies y-5=-\cfrac{5}{6}(x+6)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\textit{to get the x-intercept, we set y = 0, solve for \underline{x}}
\\\\\\
0-5=-\cfrac{5}{6}(x+6)\implies -30=5x+30\implies -60=5x
\\\\\\
\cfrac{-60}{5}=x\implies -12=x~\hfill \boxed{\stackrel{x-intercept}{(-12,0)}}


now, where's the y-intercept of that line?  well, to get the y-intercept, we set x = 0 and solve for "y"....hmmmm wait a second, notice (0, 1), x = 0, y = 1, that's the y-intercept already.

7 0
3 years ago
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