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2 years ago

Help me with these two questions plz

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

6 0

Since it says m1 is 120 and it says find m3 don’t you need to multiply or I’m wrong

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Eric has a spinner that is divided into different colored section that are the same size and shape on any spin the theoretical p

elena55 [62]

It occurred 4 more times than expected

5 0

2 years ago

Please help asap!!!

Tatiana [17]

Answer:

$w = 6$

Step-by-step explanation:

ST = w + 6,

PR = w

From the diagram given, we can deduce that PR is the midsegment of ∆QST. Therefore, according to the midsegment theorem:

PR = ½ of ST

Plug in the values into the equation and solve for w.

$w = \frac{1}{2}(w + 6)$

$w = \frac{w}{2} + 3$ (distributive property of equality)

$w - 3 = \frac{w}{2}$ (subtraction property of equality)

$2(w - 3) = \frac{w}{2}*2$ (multiplication property of equality)

$2w - 6 = w$

$2w - 6 - 2w= w - 2w$ (subtraction property of equality)

$- 6 = - w$

Divide both sides by -1

$6 = w$

$w = 6$

5 0

2 years ago

If b=5 what is b to the power of 5

Sonja [21]

Answer: 5^5 = 3125

Step-by-step explanation:

To the power of mostly means multiplying it by itself the number of times giving so for your problem it is 5 times itself 5 times so 5*5*5*5*5 = 3125

5 0

2 years ago

Read 2 more answers

A researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic

Delvig [45]

Answer:

90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

Step-by-step explanation:

We are given that a researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic meter with a standard deviation of 0.093.

Firstly, the pivotal quantity for 90% confidence interval for the population mean iron concentration is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean iron concentration = 0.802 cc/cubic meter

s = sample standard deviation = 0.093

n = number of water samples = 27

$\mu$ = population mean

Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.706 < $t_2_6$ < 1.706) = 0.90 {As the critical value of t at 26 degree of

freedom are -1.706 & 1.706 with P = 5%}

P(-1.706 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 1.706) = 0.90

P( $-1.706 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $1.706 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ , $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ]

= [ $0.802 -1.706 \times {\frac{0.093}{\sqrt{27} }$ , $0.802 +1.706 \times {\frac{0.093}{\sqrt{27} }$ ]

= [0.771 , 0.832]

Therefore, 90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

4 0

2 years ago

3 Given the function f (x) = 3.84 – 5x2 + 2x – 3, evaluate for f(

Artemon [7]

Step-by-step explanation:

f(x) = 3x⁴ - 5x² + 2x - 3

When x = -1,

f(-1) = 3(-1)⁴ - 5(-1)² + 2(-1) - 3 = 3 - 5 - 2 - 3 = -7.

3 0

2 years ago