How to calculate distance between two points (-3,2) and (3,0). And pls find the radical

Mathematics

2 answers:

Delicious77 [7]2 years ago

8 0

I think it’s y=3x-9?

irina1246 [14]2 years ago

7 0

√74
Explanation:
To calculate the distance use the
distance formula
d=√(x2−x1)^2+(y2−y1)^2

−−−2
where
(x1,y1)and (x2,y2)
are 2 coordinate points
The 2 points here are (-3 ,7) and (4 ,2)
let(x1,y1)=(−3,7) and (x2,y2)=
(4,2)⇒d=√(4−(−3))2+(2−7)2=√49+25=√74←in radical form

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the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago

Answer both ASAP! please do correctly

Tresset [83]

Answer:

1. the discriminant is 4

the number of solutions 0

solutions 0

2.the discriminant is 0

i couldn't find any solutions

Step-by-step explanation:

4 0