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BigorU [14]
4 years ago
6

The element germanium was once an important component

Chemistry
1 answer:
mario62 [17]4 years ago
4 0

Answer:

The percentage of germanium in germatite is 6.0003%.

Explanation:

Mass of an ore of germanite =  1.00 grams

Mass of germanium chloride = 0.177 grams

Percentage of germanium in germanium chloride = 33.9%

Let the mass of germanium present in germanium chloride be x.

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

33.9\%=\frac{x}{0.177 grams}\times 100

x = 0.060003 grams

Percentage of germanium in an ore of germanite:

=\frac{0.060003 gram}{1 gram}\times 100=6.0003\%

The percentage of germanium in germatite is 6.0003%.

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Number of grams of perchloric acid in 4.25 x 10^-4 mol of perchloric acid
weeeeeb [17]

Answer: 0.043g

Explanation:

chemical formular of perchloric acid is HClO4

no. of moles = mass / molar mass

n = m / mm

m = n x mm

n = 4.25 x 10^-4 mol

m = ?

mm = 1 + 35.5 + (16 x 4) = 100.5g/mol

m = 4.25 x 10^-4 mol x 100.5g/mol

m = 0.043g

7 0
3 years ago
9. How many grams of zinc are needed to produce 12 grams of zinc chloride according to the following equation? Y-
tensa zangetsu [6.8K]

Given :

A balanced chemical equation :

Zn +Cl_2->ZnCl_2

To Find :

How many grams of zinc are needed to produce 12 grams of zinc chloride.

Solution :

Moles of ZnCl_2 ,

n=\dfrac{Given \ wt}{Molecular\ Mass}\\\\n =\dfrac{12}{136.30}\ mol\\\\n=0.088\ mol

Now, by balanced chemical equation we can say that 1 mol of Zn produce

1 mol of ZnCl_2 .

So, 0.088 mol of Zn is required to produced 0.088 mol of ZnCl_2 .

Mass \ required = molecular \ mass \times moles\\\\m = 65.38 \times 0.088\\\\m=5.8 \ gm

Therefore, 5.8 grams of zinc is required.

Hence, this is the required solution.

4 0
3 years ago
The compound AL2o3 is made of?
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AL2o3 also known as Aluminium oxide is a chemical compound consisting of Aluminium and oxygen, hence AL2o3

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