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4 years ago

The element germanium was once an important component

Chemistry

1 answer:

mario62 [17]4 years ago

4 0

Answer:

The percentage of germanium in germatite is 6.0003%.

Explanation:

Mass of an ore of germanite = 1.00 grams

Mass of germanium chloride = 0.177 grams

Percentage of germanium in germanium chloride = 33.9%

Let the mass of germanium present in germanium chloride be x.

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

$33.9\%=\frac{x}{0.177 grams}\times 100$

x = 0.060003 grams

Percentage of germanium in an ore of germanite:

$=\frac{0.060003 gram}{1 gram}\times 100=6.0003\%$

The percentage of germanium in germatite is 6.0003%.

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Determine the molecular formula for the compound with a molar mass of 46.08 g/mol and the following percent compostion:

kramer

Answer:

$\large\boxed{\large\boxed{CH_6N_2}}$

Explanation:

1. First determine the empirical formula.

a) Base: 100 g of compound

mass atomic mass number of moles

g g/mol mol

C 26.06 12.011 26.06/12.011 = 2.17

H 13.13 1.008 13.13/1.008 = 13.03

N 60.81 14.007 60.81/14.007 = 4.34

b) Divide every number of moles by the smallest number: 2.17

mass number of moles proportion

C 2.17/2.17 1

H 13.03/2.17 6

N 4.34/2.17 2

c) Empirical formula

$CH_6N_2$

d) Mass of the empirical formula

$1\times 12.011g/mol6+6\times 1.008g/mol+2\times 14.007g/mol=46.07g/mol$

2. Molecular formula

Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

$CH_6N_2$

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3 years ago

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vfiekz [6]

Answer:

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4 years ago

What is the angle of refraction?

Andrej [43]

Answer:

The answer is the angle made by a refracted ray with a perpendicular to the refracting surface.

Explanation:

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3 years ago

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ss7ja [257]

Answer:

False

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3 years ago

Read 2 more answers

the length of a string is 16cm.Its length becomes 20cm when supporting a weight of 5N.Calculate the length of the string when su

guapka [62]

Answer:

Explanation:

According to hooks law "provide the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force F"

$F= ke$

where F= applied force

k= spring constant

e= extension

Given data

length of string l = 16cm

extension e = 20-16= 4cm

applied force = 5N

we need t o first calculate the spring constant k

apply the formula

$F= ke$

$5=k*4\\k= \frac{5}{4} \\k= 1.25N/cm$

we can now calculate the extension of the string when supporting a 6N weight

$F= ke\\6=1.25*e\\e= \frac{6}{1.25} \\e= 4.8cm$

The length of the string when supporting a 6N weight is

$= length+ extension\\= 16+4.8\\= 20.8cm$

COMMENT :According to the analysis an extra weight of 1N will cause add 0.8cm to the length of the string

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3 years ago