to get the equation of any straight line, we simply need two points off of it, let's use the points from the picture below then.
![(\stackrel{x_1}{-20}~,~\stackrel{y_1}{-80})\qquad (\stackrel{x_2}{40}~,~\stackrel{y_2}{-20}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-20}-\stackrel{y1}{(-80)}}}{\underset{run} {\underset{x_2}{40}-\underset{x_1}{(-20)}}}\implies \cfrac{-20+80}{40+20}\implies \cfrac{60}{60}\implies 1](https://tex.z-dn.net/?f=%28%5Cstackrel%7Bx_1%7D%7B-20%7D~%2C~%5Cstackrel%7By_1%7D%7B-80%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B40%7D~%2C~%5Cstackrel%7By_2%7D%7B-20%7D%29%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B-20%7D-%5Cstackrel%7By1%7D%7B%28-80%29%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B40%7D-%5Cunderset%7Bx_1%7D%7B%28-20%29%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-20%2B80%7D%7B40%2B20%7D%5Cimplies%20%5Ccfrac%7B60%7D%7B60%7D%5Cimplies%201)
![\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-80)}=\stackrel{m}{1}(x-\stackrel{x_1}{(-20)}) \\\\\\ y+80=x+20\implies y=x-60](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B%28-80%29%7D%3D%5Cstackrel%7Bm%7D%7B1%7D%28x-%5Cstackrel%7Bx_1%7D%7B%28-20%29%7D%29%20%5C%5C%5C%5C%5C%5C%20y%2B80%3Dx%2B20%5Cimplies%20y%3Dx-60)
Answer:
A and D are the answer.
Step-by-step explanation:
We can factor this by grouping
![2 {x}^{2} + 5x - 3](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20-%203)
![2 {x}^{2} + 6x - x - 3](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20%20%2B%206x%20-%20x%20-%203)
![2x(x + 3) -1 (x + 3)](https://tex.z-dn.net/?f=2x%28x%20%2B%203%29%20-1%20%28x%20%2B%203%29)
The roots are
![(x + 3) = 0](https://tex.z-dn.net/?f=%28x%20%2B%203%29%20%3D%200)
and
![2x - 1 = 0](https://tex.z-dn.net/?f=2x%20-%201%20%3D%200)
Let solve for zero in each roots.
![x = - 3](https://tex.z-dn.net/?f=x%20%3D%20%20-%203)
![2x = 1](https://tex.z-dn.net/?f=2x%20%3D%201)
![x = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Answer:
D
Step-by-step explanation:
x= 522-7+10+14
×=539
Pete had 539 points after the three games
<h3>
<u>Answer:</u></h3>
Average of salary of Anne and David is 1.25 of Peter's Salary
<h3>
<u>Explanation:</u></h3>
In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.
Let us assume Peter's Salary as P.
Then we can calculate Anne's salary A =
.
Also David's salary = D = ![2 \times P](https://tex.z-dn.net/?f=2%20%5Ctimes%20P)
Average of Anne's and David's salary = ![\frac{A+D}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BA%2BD%7D%7B2%7D)
Average of Anne's and David's salary = ![\frac{\frac{P}{2} + 2 \times P}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7BP%7D%7B2%7D%20%2B%202%20%5Ctimes%20P%7D%7B2%7D)
Average of Anne's and David's salary = ![\frac{5 \times P}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%20%5Ctimes%20P%7D%7B4%7D)
Average = 1.25 \times P