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lidiya [134]
3 years ago
11

Select the two values of x that are roots of this equation 2x^2+5x-3=0

Mathematics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

A and D are the answer.

Step-by-step explanation:

We can factor this by grouping

2 {x}^{2}  + 5x - 3

2 {x}^{2}   + 6x - x - 3

2x(x + 3) -1 (x + 3)

The roots are

(x + 3) = 0

and

2x - 1 = 0

Let solve for zero in each roots.

x =  - 3

2x = 1

x =  \frac{1}{2}

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
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Answer:

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-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

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