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Marat540 [252]
3 years ago
8

A nutrition label states that there are 36g of carbohydrates in each serving. This accounts for 12% of a daily value. How many g

rams of carbohydrates are recommended per day?

Mathematics
2 answers:
zzz [600]3 years ago
6 0
Here's a photo where x is the number of grams

dexar [7]3 years ago
6 0

Answer: 300 gm

Step-by-step explanation:

Given : A nutrition label states that there are 36g of carbohydrates in each serving.

This accounts for 12% of a daily value.

which can be written as 0.12.

Let x be the total grams of carbohydrates are recommended per day.

Then , we have the following equation:_

0.12x=36\\\\\Rightarrow\ x=\dfrac{36}{0.12}\\\\\Rightarrow\ x=\dfrac{3600}{12}=300

Now, the total grams of carbohydrates are recommended per day. = 300 gm

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Emanuel is renting a car for 1week in Charleston, South Carolina. The rental car agency is charging $175 for the rental and 15%
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Step-by-step explanation:

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An automobile dealer wants to see if there is a relationship between monthly sales and the interest rate. A random sample of 4 m
SVETLANKA909090 [29]

Answer:

a) y=-6.254 x +75.064  

b) r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

Step-by-step explanation:

Assuming the following dataset:

Monthly Sales (Y)     Interest Rate (X)

       22                               9.2

       20                               7.6

       10                                10.4

       45                                5.3

Part a

And we want a linear model on this way y=mx+b, where m represent the slope and b the intercept. In order to find the slope we have this formula:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=278.65-\frac{32.5^2}{4}=14.5875  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=696.9-\frac{32.5*97}{4}=-91.225  

And the slope would be:  

m=\frac{-91.225}{14.5875}=-6.254  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{32.5}{4}=8.125  

\bar y= \frac{\sum y_i}{n}=\frac{97}{4}=24.25  

And we can find the intercept using this:  

b=\bar y -m \bar x=24.25-(-6.254*8.125)=75.064  

So the line would be given by:  

y=-6.254 x +75.064  

Part b

For this case we need to calculate the correlation coefficient given by:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

r=\frac{4(696.9)-(32.5)(97)}{\sqrt{[4(278.65) -(32.5)^2][4(3009) -(97)^2]}}=-0.937  

So then the correlation coefficient would be r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

6 0
3 years ago
15 Points!! Please help and explain how to solve them!! I really want to understand it
babymother [125]
1) idk I got none of your options
2)p=42,000÷(1+0.0225÷12)^(12×5)
P=37,535.04
3)PVAO=4900*12[(1/0.029)-(1/0.029*(1+0.029)^10]=504145.41..compare with 500000
So the answer is D
4)lucas
90×87.92=7,912.8
((8,476.20−7,912.8)
÷7,912.8)×100=7.1%
Peton
55×72.03=3,961.65
((4,192.10−3,961.65)
÷3,961.65)×100=5.8%
So the answer is D
8 0
3 years ago
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