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Likurg_2 [28]
3 years ago
14

Can somebody help me with this it really hard for me

Mathematics
1 answer:
Ann [662]3 years ago
8 0
The answer is A: 125 years
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3/4 would have to be a answer
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Consider the radical equation √c+22 = c + 2.
dimulka [17.4K]

First square both sides to get:

c + 22 = (c + 2)^2

or

c + 22 = c^2 + 4c + 4

Move the terms on the left side to the right side:

c^2 + 3c - 18 = 0

Factor to get:

(c + 6) * (c - 3) = 0.

The solutions are c = -6 and c = 3.

Check to see if these answers work by plugging them into the original equation:

c = -6:

sqrt (-6 + 22) ?= -6 + 2

But, -6 + 2 is a negative number, and you can't get a negative from a square root. So, -6 is extraneous.

c = 3:

sqrt (3 + 22) ?= 3 + 2

5 = 5. So, 3 works.

The answer is: B

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Determine the measure of the third angle. * o 48° O 62° O 70° 132 180°
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Step-by-step explanation:

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3 years ago
Solve this equation. Enter your answer in the box. 75 â€"" 3. 5y â€"" 4y = 4y 6.
Liula [17]

Answer:

Solve this equation. Enter your answer in the box. 75 â€"" 3. 5y â€"" 4y = 4y 6.

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Determine whether the three given points are collinear. (3, 2), (4, 6), (0, 8) True: they are collinear False: they are not coll
FinnZ [79.3K]

Answer:

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Step-by-step explanation:

For three point's to be co linear the slopes of the lines connecting them should be same

Mathematically we can write for (x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})

to be co-linear we should have

\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{y_{3}-y_{1}}{x_{3}-x_{1}}

Applying the given values we obtain

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As we can see the values are not equal thus the points are not co-linear.

6 0
3 years ago
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