Question

(2,-1);y=-3/2x+6 how do you solve this equation?

Answer 1

Answer:

$y = - \frac{3}{2}x + 2$

Step-by-step explanation:

Assuming the question wants you to write and equation passing through (2,-1); and parallel to y=-3/2x+6.

Then we use the slope intercept form:

$y-y_1=m(x-x_1)$

We substitute the point and slope to get:

$y - - 1 = - \frac{3}{2} (x - 2)$

$y + 1 = - \frac{3}{2}x - + 3$

$y = - \frac{3}{2}x + 3 - 1$

$y = - \frac{3}{2}x + 2$

Note that parallel lines have the same gradient.